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Winkler's Level 3 Burr


Winkler's Level 3 Burr Design : David V. Winkler.

A#959 B#255 C#255
D#255 E#255 F#255
Pieces 6 B-F are congruent.
Length 6
Holes 9
Solutions 1 / 1
Moves 3

My question: Why doesn't he use #927 instead of #959?
Winkler answered: This was a burr to demonstrate a bug in the IBM web burr solver. The symmetric piece is more satisfying, but this one was the one that exposed the bug.


Apr 30, 2001 by k16@chiba.email.ne.jp