Trinomial Cube #3
Design and Copyright : Ernest Treloar (2013).
(a, b, c) = (2, 3+α, 4-α).
☞ “Trinomial Cube” Puzzles
A |
a³ + abc + bc² + a²b + b²c |
B |
2ac² + ab² + abc + bc² |
C |
a²b + 3a²c + abc |
D |
2ab² + b²c + b³ |
E |
3abc + b²c |
F |
a²b + ac² + bc² + c³ |
|
Pieces | 6 |
Selection | random |
Goal | 9×9×9 |
Holes | 0 |
Solutions | 1 |
Jan 25, 2013 by
k16@chiba.email.ne.jp