Trinomial Cube #3
Design and Copyright : Ernest Treloar (2013).
(a, b, c) = (2, 3+α, 4-α).
☞ “Trinomial Cube” Puzzles
| A | 
a³ + abc + bc² + a²b + b²c |
B | 
2ac² + ab² + abc + bc² |
C | 
a²b + 3a²c + abc |
| D | 
2ab² + b²c + b³ |
E | 
3abc + b²c |
F | 
a²b + ac² + bc² + c³ |
|
| Pieces | 6 |
| Selection | random |
| Goal | 9×9×9 |
| Holes | 0 |
| Solutions | 1 |
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EEECCBBBB | EEECCBBBB | EEECCBBBB | EEECCBBBB | AACCCCCCC | AACCCCCCC | AAAAAAAAA | AAAAAAAAA | AAAAAAAAA
EEECCBBBB | EEECCBBBB | EEECCBBBB | EEECCBBBB | AACCCCCCC | AACCCCCCC | AAAAAAAAA | AAAAAAAAA | AAAAAAAAA
EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | FFFFEEECC | FFFFEEECC | AAAAAAAAA | AAAAAAAAA | AAAAAAAAA
EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | FFFFEEECC | FFFFEEECC | AAAAAAAAA | AAAAAAAAA | AAAAAAAAA
EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | EEEEEBBBB | FFFFEEECC | FFFFEEECC | DDDAACCCC | DDDAACCCC | DDDAACCCC
FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFFFEEECC | FFFFEEECC | DDDAACCCC | DDDAACCCC | DDDAACCCC
FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFBBBBBBB | FFBBBBBBB | DDDDDDDDD | DDDDDDDDD | DDDDDDDDD
FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFBBBBBBB | FFBBBBBBB | DDDDDDDDD | DDDDDDDDD | DDDDDDDDD
FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFFFFFFBB | FFBBBBBBB | FFBBBBBBB | DDDDDDDDD | DDDDDDDDD | DDDDDDDDD
Jan 25, 2013 by
k16@chiba.email.ne.jp